Today we will discuss about heat and some interesting phenomenon
happened due to heat. And we also discuss about our topic which is “how much
there will be temperature of the resultant liquid (water), if we add cold water
into hot water.”
Before we start we must understand heat and temperature. to know what is heat and temperature and what is difference between heat and temperature,
NOW let’s start our topic
We will find the answer of the question, when both liquid are same (i.e.
both are water). and we also know what will be temperature of the resultant
liquid, when both liquid are different.
Let’s take a question and try youself.
Q). 100 g of water at 10 ℃ is mixed with 200 g of water at 70 ℃. what will be final temperature of the mixture?
The branch of physics which deals with measurement of heat is called Calorimetry.
And the device which is used to measure heat is called calorimeter.
The principal of calorimeter or heat balance states that
HEAT
LOSS=HEAT GAIN
That means the amount of heat loosed by a system is equal to the heat
gained by other system. The system whose temperature is more than its surrounding
loses heat and surrounding gains the heat lost by the system.
Heat always flows from hot body (high temperature) to cold body (low temperature)
Consider a system A of mass m1, specific heat C1
and temperature T1 .
let and another system B whose mass is m2,
specific heat C2 and temperature T2 is
brought in contact of system a.
If temperature of system A (T1) >
temperature of system B (T2)
Then heat will be flow from system A to system B till
these two system are in thermal equilibrium at temperature T ,mean heat
will be flow from system A to system B till these two system not having same temperature
T.
i.e. final temperature =T
now,
Heat loosed by system A = m1C1 (T1-T)
Heat gained by system B = m2C2(T-T2)
According to The principal of calorimeter
HEAT LOSS = HEAT GAIN
m1C1 (T1-T)
= m2C2(T-T2)
Now you can able to find the temperature
of resultant solution of two different liquid.
If both liquid are same then formula
will be
m1 (T1-T) = m2(T-T2)
Here C1 and C2 will be same because specific
heat of both system (liquid) are same. Know more about specific heat capacity
at the end of this page.
Q). 100 g of water at 10 ℃ is mixed with 200 g of water at 70 ℃. what will be final temperature of the mixture?
In system A,
Mass of water= 200g
Temperature = 70 ℃
In system A,
Mass of water= 100g
Temperature = 10 ℃
Let final temperature =T
According to The principal of calorimeter
HEAT LOSS = HEAT GAIN
m1C1 (T1-T)
= m2C2(T-T2)
Here C1 and C2 will be same because both
liquid are same and specific heat of
both system are same.
∴ m1 (T1-T) = m2(T-T2)
200 (70 - T) = 100 ( T – 10)
2 (70
- T) = T – 10
140 - 2T
=T – 10
3T = 150
T = 50℃
Therefore, final temperature of the mixture=50℃
Important topic
Important topic
………………………………………………………
What is specific heat?
Ans-Specific heat capacity of a substance is defined as the amount of heat
required to raise the temperature of 1g of substance through 1℃.
When a
body is heated its temperature increases on the otherhand, temperature of body
decreases when it is cooled it is found that the loss or gain of heat is
directly proportional to
Q ∞ m
(mass of the body)
Q ∞ ∆T(change
in temperature of the body)
∴ Q ∞
m∆T
or, Q=C m∆T
where C
is proportionality constant and it is known as specific heat.
It
depends on the nature of the material of the body.
Thus , Heat transferred = mass of the body x
specific heat x change in temperature
If m=1g and ∆T=1℃
Then
Q=C
Therefore,
Specific heat capacity of a substance is defined as the amount of heat required
to raise the temperature of 1g of substance through 1℃.
∴ C=Q/ m∆T
- · SI unit of specific heat is J/kg K ,
- · Dimensional formula [M0L2T-2K-1]
- · Table of specific heat capacity of various substance.
Substance
|
c in J/gm K
|
Aluminum
|
0.900
|
Copper
|
0.386
|
Gold
|
0.126
|
Silver
|
0.233
|
Tungsten
|
0.134
|
Zinc
|
0.387
|
Mercury
|
0.140
|
Alcohol(ethyl)
|
2.4
|
Water
|
4.186
|
Ice (-10 C)
|
2.05
|
Glass
|
.84
|
Thank you
For any confusion ,comment below .
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